codecool codecool - 4 months ago 27x
Python Question

Creating link to an url of Flask app in jinja2 template

In my Flask app, I have a view which displays a post

def get_post(year,month,title):
# My code

To display the last 10 entries, I have following view:

def get_all_posts():
# My code
return render_template('p.html',posts=posts)

Now when I display the last 10 posts, I want to convert the title of a post into a hyperlink.
Currently I have to do the following in my jinja template to achieve this:

<a href="/post/{{year}}/{{month}}/{{title}}">{{title}}</a>

Is there any way to avoid hard coding the url?

function which is used to create Flask urls like this:


I have tried searching for one but I,m not able to find it.


I feel like you're asking two questions here but I'll take a shot...

For the posting url you'd do this:

<a href="{{ url_for('post_blueprint.get_post', year=year, month=month, title=title)}}">
    {{ title }}

To handle static files I'd highly suggest using an asset manager like Flask-Assets, but to do it with vanilla flask you do:

{{ url_for('static', filename='[filenameofstaticfile]') }}

If you'd like more information I highly suggest you read. and

Edit for using kwargs:

Just thought I'd be more thorough...

If you'd like to use url_for like this:

{{ url_for('post_blueprint.get_post', **post) }}

You have to change your view to something like this:

def get_all_posts():
    models = database_call_of_some_kind # This is assuming you use some kind of model
    posts = []
    for model in models:
        posts.append(dict(year=model.year, month=model.month, title=model.title))
    return render_template('p.html', posts=posts)

Then your template code can look like this:

{% for post in posts %}
    <a href="{{ url_for('post_blueprint.get_post', **post) }}">
        {{ post['title'] }}
{% endfor %}

At this point I would actually create a method on the model so you don't have to turn it into a dict, but going that far is up to you :-).