why why - 1 year ago 72
Java Question

Java nested generic type mismatch

In the following example:

public static void main(String[] args) {

List<String> b = new ArrayList<String>();

List<List<String>> a = new ArrayList<List<String>>();
fourth(a); // doesnt work


private static <T> void first(List<T> a){
System.out.println("List of T");

private static void second(List<?> a){
System.out.println("List of anything ");

private static <T> void third(List<List<T>> a){
System.out.println("List of a List of T ");

private static void fourth(List<List<?>> a){
System.out.println("List of a List of anything ");

Why does the call to second(b) work, but the call to fourth(a) doesn't ?

I get the following error:

The method fourth(List<List<?>>) in the type `TestTest` is not applicable for the arguments (`List<List<String>>`)

Answer Source

If you want to be able to call fourth with a List<List<String>> argument, then you'll need to change your signature to this:

private static void fourth(List<? extends List<?>> a){
    System.out.println("List of a List of anything ");

The above will work because unlike List<List<?>>, List<? extends List<?>> is compatible with List<List<String>>. Think of it this way:

List<List<String>> original = null;
List<? extends List<?>> ok  = original; // This works
List<?> ok2                 = original; // So does this
List<List<?>> notOk         = original; // This doesn't

List<Integer> original      = null;
List<? extends Number> ok   = original; // This works
List<?> ok2                 = original; // So does this
List<Number> notOk          = original; // This doesn't

The reasoning is simple. If you had

private static void fourth(List<List<?>> a) {
    List<?> ohOh = Arrays.asList(new Object());

And then if you could call that method as such:

List<List<String>> a = new ArrayList<List<String>>();
String fail = a.get(0).get(0); // ClassCastException here!
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