Lazyexpert Lazyexpert - 1 month ago 9x
Node.js Question

Array forEach pass "push" as argument

Faced strange issue in JS. I receive error on this:

let a = []
let b = [1,2,3]
TypeError: Array.prototype.push called on null or undefined
at Array.forEach (native)
at repl:1:3
at REPLServer.defaultEval (repl.js:262:27)
at bound (domain.js:287:14)
at REPLServer.runBound [as eval] (domain.js:300:12)
at REPLServer.<anonymous> (repl.js:431:12)
at emitOne (events.js:82:20)
at REPLServer.emit (events.js:169:7)
at REPLServer.Interface._onLine (readline.js:211:10)
at REPLServer.Interface._line (readline.js:550:8)

Sure, I've made a suggestion, that the context is lost. So, I try to accomplish that in this way:


The result becomes unpredictable:

[ 1, 0, [ 1, 2, 3 ], 2, 1, [ 1, 2, 3 ], 3, 2, [ 1, 2, 3 ] ]

WHAT? =) Where is 0 from? Okay, maybe its "glitch"-index, but why not first than? :)

Just to make it clear, this works in a classical way, and that's not a question:

b.forEach(el => a.push(el) )

Can someone explain this strange behaviour?


Basically as per the standard syntax of forEach, it is having 3 different parameters, current item, index and the array over which the forEach is called. So push function which was bound with a will be called every time with those parameters. That is the issue here.

iteration 1 : a.push(1,0,[1,2,3]) //since a was bound with push
iteration 2 : a.push(2,1,[1,2,3])
iteration 3 : a.push(3,2,[1,2,3])

Your code will be executed like above.