Harwee Harwee - 2 years ago 130
Python Question

Subprocess returns exit status 1

When I run a command through subprocess I get exit status 1 without my print or the error raised.

here is my code:

def generate_model(self):
if not ((self.username == None) or (self.password == None) or (self.database == None)):
cmd = "python -m pwiz -e %s -H %s -u %s -P %s %s > %s"%(self.engine,self.host,self.username,self.password,self.database,self.database+".py")
print subprocess.check_call(cmd)
raise ValueError

command asks an input once terminal is opened. After that it closes with
exit status 1

When I run the same command directly in command prompt it works fine

Answer Source

subprocess.check_call() does not run the shell by default and therefore the redirection operator > won't work. To redirect stdout, pass stdout parameter instead:

with open(filename, 'wb', 0) as file:
    check_call([sys.executable, '-m', 'pwiz', '-e', ...], stdout=file)

Related: Python subprocess.check_output(args) fails, while args executed via Windows command line work OK.

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