Eric Freese Eric Freese - 1 year ago 63
Objective-C Question

Nil NSDate when trying to get date from UTC string in zulu time

Writing an iPhone app in Objective-C, I have a date in string form (in UTC format, with a Z on the end to denote zero UTC offset, or zulu time), which I need to parse into an


A bit of code:
NSDateFormatter* df = [[NSDateFormatter alloc]init];
[df setDateFormat:@"yyyy-MM-dd'T'HH:mm:ss.SSSZ"];
NSString* str = @"2009-08-11T06:00:00.000Z";
NSDate* date = [df dateFromString:str];

Running this through the debugger,
ends up
! I'm assuming it has something to do with my date format string.

How can I fix it to correctly parse the date string?

A thought would be to make the
in the date format literal, a la setting the date format to

That would work, except when the Z is parsed as a literal, the date loses offset information, and so is ambiguous, and therefore interpreted to be local time.

For example, if the string to parse was 2009-08-11T06:00:00.000Z (6:00 zulu time) it would be interpreted as 6:00 local time, and an incorrect offset would then be applied. It would then be parsed as 2009-08-11T06:00:00.000-600 (12:00 zulu time) with the offset depending on the user's offset.


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Answer Source

I've had this problem also, I'm not sure if it's a API bug within Apple's code, or my lack of understanding, but I've worked around it by using hour offsets in my date strings.

If you change the code in your example to:

NSDateFormatter* df = [[NSDateFormatter alloc]init];
[df setDateFormat:@"yyyy-MM-dd'T'HH:mm:ss.SSSZ"];
NSString* str = @"2009-08-11T06:00:00.000-0700";   // NOTE -0700 is the only change
NSDate* date = [df dateFromString:str];

It will now parse the date string. Of course the -0700 hours is my offset, you'd have to change it to yours. Hope this helps.

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