Serge Rogatch - 11 months ago 78

C++ Question

I have an array of bytes where each byte is either 0 or 1. Now I want to pack these values into bits, so that 8 original bytes occupy 1 target byte, with original byte 0 going into bit 0, byte 1 into bit 1, etc.

So far I have the following in the kernel:

`const uint16_t tid = threadIdx.x;`

__shared__ uint8_t packing[cBlockSize];

// ... Computation of the original bytes in packing[tid]

__syncthreads();

if ((tid & 4) == 0)

{

packing[tid] |= packing[tid | 4] << 4;

}

if ((tid & 6) == 0)

{

packing[tid] |= packing[tid | 2] << 2;

}

if ((tid & 7) == 0)

{

pOutput[(tid + blockDim.x*blockIdx.x)>>3] = packing[tid] | (packing[tid | 1] << 1);

}

Is this correct and efficient?

Answer Source

The `__ballot()`

warp-voting function comes quite handy for this.
Assuming that you can redefine `pOutput`

to be of `uint32_t`

type, and that your block size is a multiple of the warp size (32):

```
unsigned int target = __ballot(packing[tid]);
if (tid % warpSize == 0) {
pOutput[(tid + blockDim.x*blockIdx.x) / warpSize] = target;
}
```

Strictly speaking, the if conditional isn't even necessary, as all threads of the warp will write the same data to the same address. So a highly optimized version would just be

```
pOutput[(tid + blockDim.x*blockIdx.x) / warpSize] = __ballot(packing[tid]);
```