Jared Sanchez Jared Sanchez - 1 year ago 70
Python Question

python global variable scope confusion. What are these variables not accessible?

I see there are a few of these questions on here, but I haven't found one that quit matches what I'm after.

I have a common file, lets call it tools.py. In this file I have a host of path definitions to use and an init_paths function to set some key paths based on command line arguments:

def init_paths(args):
global tools_dir, tools_src, tools_bin

if args.tools_set:
tools_dir = os.path.realpath(os.path.join(args.tools_set,"tools"))
tools_dir = os.path.join(BAR_PATH, "tools")

FOO_PATH = os.path.realpath(os.path.join(os.path.dirname(os.path.realpath(__file__)), ".."))
BAR_PATH = os.path.join(FOO_PATH, "foobar")
tools_dir = none
tools_src = none
tools_bin = none


I have a main file, lets call it main.py where I want to use these.

if __name__ == "__main__":
args = parseArgs()
from tools import init_paths
doStuffFunction(args.one, args.two, args.three)

I have left out the meat and potatoes to be sure, but I believe this should be enough to illustrate my global scope problem. when I run this:
python main.py --tools-set=/path/to/tools
, I am expecting the call to init_paths, to set up some key paths I wish to use later in the

def doStuffFunction():
searchPath = os.path.join(tools_dir, "folder")

this fails: AttributeError: 'NoneType' object has no attribute endswith

pretty sure this is because it is not getting set. but why?



#!/usr/bin/env python
import sys
import os
import argparse
import glob
from tools import *

def parseArgs():
parser = argparse.ArgumentParser(description="parse my args")
parser.add_argument("--toolchain-root", type=str,default=None,help='specify toolchain directory')
args = parser.parse_args()

return args

def doStuffFunction():
output = 'output'
if not os.path.isdir(output):

def gimmySugar(output):
fileList = []
linkBook= {}

searchPath = os.path.join(tools_BIN_ROOT,'gcc-4.8.5')
for root, dirs, files in os.walk(searchPath):
for libFile in glob.glob(root+'/*.so*'):
if os.path.islink(libFile):
linksWith = os.readlink(libFile)
linkBook[libFile] = linksWith

if __name__ == "__main__":
# script was called directly from the command line
args = parseArgs()
from tools import init_settings


import os

def init_settings(args):
global tools_DIR, tools_SRC_ROOT, tools_OBJ_ROOT, tools_BIN_ROOT
if args.toolchain_root:
tools_DIR = os.path.realpath(os.path.join(args.toolchain_root, "toolchain"))
tools_DIR = os.path.join(USER_DIR, "")
tools_SRC_ROOT = os.path.join(tools_DIR, "src")
tools_OBJ_ROOT = os.path.join(tools_DIR, "obj")
tools_BIN_ROOT = os.path.join(tools_DIR, "bin")

ROOT_PATH = os.path.realpath(os.path.join(os.path.dirname(os.path.realpath(__file__)), ".."))
OUTPUT_PATH = os.path.join(ROOT_PATH, "outputs")
BUILD_PATH = os.path.join(OUTPUT_PATH, "build")
USER_DIR = "/usr/lib64/"
tools_DIR = None
tools_SRC_ROOT = None
tools_OBJ_ROOT = None
tools_BIN_ROOT = None

Answer Source
#This line will failed
searchPath = os.path.join(tools_BIN_ROOT,'gcc-4.8.5')

The scope of global variables is module level, tools_BIN_ROOT will not be shared without passing across modules.

The variable tools_BIN_ROOT is global variable ONLY in tools.py. Insteadly, main.py do not contain any global variable in tools.py.

For inspecting this, you can use print(globals()) in both files.

Do not use global variable if possible.

This is a simple workaround.

(I strongly recommend you to refactor your code by config or OOP)


def get_tools_BIN_ROOT():
    return tools_BIN_ROOT


from tools import get_tools_BIN_ROOT
searchPath = os.path.join(get_tools_BIN_ROOT(),'gcc-4.8.5')
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