marbel - 2 months ago 9

R Question

Some data:

`require(data.table)`

set.seed(123)

DT <- data.table(factor = c("a", "b", "c"), num = rpois(6, 30))

DT[["factor"]] <- factor(DT[["factor"]])

levels(DT[["factor"]])

# [1] "a" "b" "c"

I'm trying to write a function that gets the levels of the the DT. Here's what I've attempted so far:

`get_levels <- function(data, factor){`

data = substitute(data)

factor = substitute(factor)

factor_levels = levels(data[["factor"]])

print(factor_levels)

}

get_levels(DT, factor)

get_levels2 <- function(data, factor){

data = substitute(data)

factor = substitute(factor)

factor_levels = levels(data[[factor]])

print(factor_levels)

}

get_levels2(DT, factor)

get_levels3 <- function(data, factor){

data = substitute(data)

factor = substitute(factor)

factor_levels = levels(eval(data[[deparse(factor)]]))

print(factor_levels)

}

get_levels3(DT, factor)

I'm getting this error:

`Error in data[["factor"]] : object of type 'symbol' is not subsettable`

and this one:

`Error in data[[deparse(factor)]] :`

object of type 'symbol' is not subsettable

As i don't have much experience programming i don't know exactly what's the purpose for the functions used for passing variables in functions:

`substitute`

`deparse`

`eval`

`parse`

Answer

If you're not experienced with R (or programming in general) avoid `substitute`

, `deparse`

, `eval`

, etc. They are rarely necessary.

```
DT <- data.table(f = c("a", "b", "c"), num = rpois(6, 30))
DT[["f"]] <- factor(DT[["f"]])
get_levels <- function(data,fac){
levels(data[[fac]])
}
get_levels(DT,'f')
```

And don't call your column `factor`

. That's a function, and it's just confusing.