irishwill200 irishwill200 - 1 year ago 74
PHP Question

PHP displaying first letter of array in dropdown?

My issue is that the dropdown is actually populating correctly but with only the first letter of that particular line.

I have the following in my file:




It is displaying as:




Any ideas?

My code:

<select id="playlist_wrongstyle" class="form-control" style="visibility:visible; width:250px;">
<option selected="selected">Choose one</option>
$returnedScheduleNamesArray = explode ("\n", file_get_contents('/srv/http/schedulenames'));
array_pop($returnedScheduleNamesArray); //remove empty last line
foreach($returnedScheduleNamesArray as $name)
{ ?>
<option value="<?=$name['name']?>"><?=$name['name']?></option>
} ?>

Answer Source

$name is a string. You should just echo name: <?= $name >

The reason you are seeing a single letter instead of an error:

  • String characters can be accessed using array bracket syntax:

    $name = 'Monday';
    $name[0] === 'M'; // true
  • PHP is coercing your string 'name' into an integer, and this evaluates to 0:

    (int)'name' === 0; // true
  • So, $name['any string'] === $name[0]; // true

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