C Question
How do I change the array Input Order in C
I need to input five numbers and then a positive or negative. The order will be changed like the number.
For example, if three (3) is the number then:
1 2 3 4 5 6 7 8 9 10
will become:
4 5 6 7 8 9 10 1 2 3
Please do not use pointers. I have made the following code and would like to be able to improve on it. Can I use a mathematical formula using the modulus operator
%Thanks, this is my code.
#include<stdio.h>
#define n 10
int main(void)
{
int num[n] = { 0 }, assist[n] = { 0 }, i = 0, j = 0, variable = 0, k = 0;
for (i = 0; i < n; i++)
{
printf("please enter index. %d\n", i );
scanf("%d", &num[i]);
}
printf("please enter the circle number\n");
scanf("%d", &variable);
printf("\n\n");
if (variable >= 0)
{
for (i = variable, j = 0; i < n; i++, j++)
{
assist[j] = num[i];
k++;
}
for (i = 0, j = k; i < variable, j < n; i++, j++)//to assist//
{
assist[j] = num[i];
}
}
if(variable < 0)
{
for (i = n + variable, j = 0; i < n; i++, j++)
{
assist[j] = num[i];
k++;
}
for (i = 0, j = k; i < n + variable, j < n; i++, j++)
{
assist[j] = num[i];
}
}
for (i = 0; i < n; i++)//output//
{
printf("%d\n", assist[i]);
}
return 0;
}
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Answer Source
Something like this. I did not compile; any small mistakes are for you.
#include<stdio.h>
#define N 10
int main(void)
{
int numbers[N];
int offset;
for (int i = 0; i < N; i++)
{
printf("please enter number %d: ", i);
scanf("%d", &num[i]);
}
printf("\nplease enter the circle number: ");
scanf("%d", &offset);
printf("\n\n");
for (int i = 0; i < N; i++)
{
printf("%d ", num[(i + offset) % N]);
}
printf("\n");
}
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