alon davidi - 7 months ago 90

C Question

I need to input five numbers and then a positive or negative. The order will be changed like the number.

For example, if three (3) is the number then:

1 2 3 4 5 6 7 8 9 10

will become:

4 5 6 7 8 9 10 1 2 3

Please do not use pointers. I have made the following code and would like to be able to improve on it. Can I use a mathematical formula using the modulus operator

`%`

Thanks, this is my code.

`#include<stdio.h>`

#define n 10

int main(void)

{

int num[n] = { 0 }, assist[n] = { 0 }, i = 0, j = 0, variable = 0, k = 0;

for (i = 0; i < n; i++)

{

printf("please enter index. %d\n", i );

scanf("%d", &num[i]);

}

printf("please enter the circle number\n");

scanf("%d", &variable);

printf("\n\n");

if (variable >= 0)

{

for (i = variable, j = 0; i < n; i++, j++)

{

assist[j] = num[i];

k++;

}

for (i = 0, j = k; i < variable, j < n; i++, j++)//to assist//

{

assist[j] = num[i];

}

}

if(variable < 0)

{

for (i = n + variable, j = 0; i < n; i++, j++)

{

assist[j] = num[i];

k++;

}

for (i = 0, j = k; i < n + variable, j < n; i++, j++)

{

assist[j] = num[i];

}

}

for (i = 0; i < n; i++)//output//

{

printf("%d\n", assist[i]);

}

return 0;

}

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Answer Source

Something like this. I did not compile; any small mistakes are for you.

```
#include<stdio.h>
#define N 10
int main(void)
{
int numbers[N];
int offset;
for (int i = 0; i < N; i++)
{
printf("please enter number %d: ", i);
scanf("%d", &num[i]);
}
printf("\nplease enter the circle number: ");
scanf("%d", &offset);
printf("\n\n");
for (int i = 0; i < N; i++)
{
printf("%d ", num[(i + offset) % N]);
}
printf("\n");
}
```

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