Gilgamesch von Uruk Gilgamesch von Uruk - 1 year ago 223
Python Question

Python error: "socket.error: [Errno 11] Resource temporarily unavailable" when sending image

I want to make a program that accesses images from files, encodes them, and sends them to an server.
Than the server is supposed to decode the image, and save it to file.
I tested the image encoding itself, and it worked, so the problem lies in the server and client connection.

Here is the server:

import socket
import errno
import base64

from PIL import Image
import StringIO

def connect(c):
image = c.recv(8192)
return image
except IOError as e:
if e.errno == errno.EWOULDBLOCK:

def Main():
host = ''
port = 12345

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM, socket.IPPROTO_TCP)
s.bind((host, port))

while True:

c, addr = s.accept()

print "Connection from: " + str(addr)

image = c.recv(8192)#connect(c)

imgname = 'test.png'

fh = open(imgname, "wb")
if image == 'cusdom_image':
with open('images.png', "rb") as imageFile:
image = ''
image = base64.b64encode(
print image

if __name__ == '__main__':

And here is the client:

import socket
import base64

from PIL import Image
import StringIO
import os, sys

ip = ''
port = 12345
print 'Add event executed'
s = socket.socket()
s.connect((ip, port))

image_path = '/home/gilgamesch/Bilder/Bildschirmfoto.png'

print os.getcwd()
olddir = os.getcwd()
print os.getcwd()

if image_path != '':
with open(image_path, "rb") as imageFile:
image_data = base64.b64encode(
print 'open worked'
image_data = 'cusdom_image'




And the error message is:

Traceback (most recent call last):
File "", line 49, in <module>
File "", line 34, in Main
image = c.recv(8192)#connect(c)
socket.error: [Errno 11] Resource temporarily unavailable

Answer Source

In the server you are setting the remote socket (that returned by accept()) to non-blocking mode, which means that I/O on that socket will terminate immediately by an exception if there is no data to read.

There will usually be a period of time between establishing the connection with the server and the image data being sent by the client. The server attempts to immediately read data from the client once the connection is accepted, however, there might not be any data to read yet, so c.recv() raises a socket.error: [Errno 11] Resource temporarily unavailable exception. Errno 11 corresponds to EWOULDBLOCK, so recv() aborted because there was no data ready to read.

Your code does not seem to require non-blocking sockets because there is an accept() at the top of the while loop, and so only one connection can be handled at a time. You can just remove the call to c.setblocking(0) and this problem should go away.