piRSquared - 1 year ago 71

Python Question

observe

`np.nan < 0`

False

`np.array([np.nan]) < 0`

array([False], dtype=bool)

However

`np.array([-1, np.nan]) < 0`

`//anaconda/envs/3.5/lib/python3.5/site-packages/ipykernel/__main__.py:1: RuntimeWarning: invalid value encountered in less`

if \__name\__ == '\__main\__':

`array([ True, False], dtype=bool)`

What does that error mean?

Answer Source

This is only a warning, not an exception. Numpy tries to be helpful and reports that you have a `nan`

in your array. It's safe to ignore it. If the warning itself bothers you (or your users), you can suppress it:

```
with np.errstate(invalid='ignore'):
np.less([np.nan, 0], 1)
```

However, this is really not recommended since it can mask less obvious issues and make debugging harder if you need to find where a `nan`

comes from in a lengthy calculation.

Note the semantics of a `nan`

: `nan > 0`

, `nan < 0`

and `nan < nan`

, `nan == nan`

are all `False`

.

Also note that in numpy (unlike e.g. pandas) `nan`

really means *invalid* not *not available*.