I would like to know is there any command/expression to get only the file name in hadoop. I need to fetch only the name of file, when I do "hadoop fs -ls" it prints the whole path. What is the best way to cut only the file name, I tried below but just wondering if some better way to do it.
hadoop fs -ls |cut -d ' ' -f17
It seems hadoop ls does not support any options to output just the filenames, or even just the last column.
If you want get the last column reliably, you should first convert the whitespace to a single space, so that you can then address the last column:
hadoop fs -ls | sed '1d;s/ */ /g' | cut -d\ -f8
This will get you just the last column but files with the whole path. If you want just filenames, you can use basename as @rojomoke suggests:
hadoop fs -ls | sed '1d;s/ */ /g' | cut -d\ -f8 | xargs -n 1 basename
I also filtered out the first line that says
Found ?x items
Note: beware that, as @felix-frank notes in the comments, that the above command will not correctly preserve file names with multiple consecutive spaces. Hence a more correct solution proposed by Felix:
hadoop fs -ls /tmp | sed 1d | perl -wlne'print +(split " ",$_,8)'