Ben - 1 year ago 49

SQL Question

When subtracting

`timestamps`

`interval`

The following would work, but it's not very pretty:

`select abs( extract( second from interval_difference )`

+ extract( minute from interval_difference ) * 60

+ extract( hour from interval_difference ) * 60 * 60

+ extract( day from interval_difference ) * 60 * 60 * 24

)

from ( select systimestamp - (systimestamp - 1) as interval_difference

from dual )

Is there a more elegant method in SQL or PL/SQL?

Answer Source

I hope this help:

```
zep@dev> select interval_difference
2 ,sysdate + (interval_difference * 86400) - sysdate as fract_sec_difference
3 from (select systimestamp - (systimestamp - 1) as interval_difference
4 from dual)
5 ;
INTERVAL_DIFFERENCE FRACT_SEC_DIFFERENCE
------------------------------------------------------------------------------- --------------------
+000000001 00:00:00.375000 86400,375
```

With your test:

```
zep@dev> select interval_difference
2 ,abs(extract(second from interval_difference) +
3 extract(minute from interval_difference) * 60 +
4 extract(hour from interval_difference) * 60 * 60 +
5 extract(day from interval_difference) * 60 * 60 * 24) as your_sec_difference
6 ,sysdate + (interval_difference * 86400) - sysdate as fract_sec_difference
7 ,round(sysdate + (interval_difference * 86400) - sysdate) as sec_difference
8 ,round((sysdate + (interval_difference * 86400) - sysdate) * 1000) as millisec_difference
9 from (select systimestamp - (systimestamp - 1) as interval_difference
10 from dual)
11 /
INTERVAL_DIFFERENCE YOUR_SEC_DIFFERENCE FRACT_SEC_DIFFERENCE SEC_DIFFERENCE MILLISEC_DIFFERENCE
------------------------------------------------------------------------------- ------------------- -------------------- -------------- -------------------
+000000001 00:00:00.515000 86400,515 86400,515 86401 86400515
zep@dev>
```