Hi I am not a java programmer but am trying to debug someone else's code.
I have windows bat file with java.exe -classpath followed by a very lengthy list. How do I find which java program is the entry point -- or in other words what the heck actually executes?
As requested here is the first part of the command
C:\DSUpload\java\bin\java.exe -classpath C:\DSUpload.adf;C:\DSUpload\classes;C:\DSUpload\wlserver_10.3\server\lib\weblogic.jar;
The java class file will probably be the last part of the command, if not, then it will be the only part of the command that is not preceded by a flag/option.
java -cp foo;bar;baz JavaClass
Here, "JavaClass" is the class being run, as it is below:
java -cp foo;bar;baz JavaClass -d someDir
The entry point of a java program is always its "main" method, which has the following signature (the parameter name can vary):
public static void main(String args)