ZE16 - 1 month ago 4x

Python Question

At each time step, I am trying to replace one element of my

`list`

`def replace(x, y, z):`

for i in range(3):

rep_x = [y+z+1, y, z]

rep_y = [x, x+z+1, z]

rep_z = [x, y, x+y+1]

ini_x = rep_x

ini_y = rep_y

ini_z = rep_z

return ini_x, ini_y, ini_z

print replace(2, 4, 6)

This gives me a single line - a one-time replacement. I would like the code to keep doing the replacements on the newly-obtained arrays every time, for example:

([11, 4, 6], [2, 9, 6], [2, 4, 7])

((11, 4, 6], [11, 18, 6], [11, 4, 16]), ([19, 9, 6], [2, 9, 6], [2, 9, 12]), ([12, 4, 7], [2, 10, 7], [2, 4, 7]))

How can I do this?

Answer

Is this helpful:

```
def replace(x, y, z):
ini_x = [y+z+1, y, z]
ini_y = [x, x+z+1, z]
ini_z = [x, y, x+y+1]
return ini_x, ini_y, ini_z
s = replace(2, 4, 6)
print s
for i in s:
print replace(i[0], i[1], i[2])
```

output:

```
([11, 4, 6], [2, 9, 6], [2, 4, 7])
([11, 4, 6], [11, 18, 6], [11, 4, 16])
([16, 9, 6], [2, 9, 6], [2, 9, 12])
([12, 4, 7], [2, 10, 7], [2, 4, 7])
```

Source (Stackoverflow)

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