Cheryl Perry Cheryl Perry - 1 month ago 10
PHP Question

Warning: mysql_connect(): Access denied for user 'root'@'localhost' (using password: YES)


Warning: mysql_connect(): Access denied for user 'root'@'localhost'
(using password: YES) in C:\xampp\htdocs\Login\sessionHandler.php on
line 35


So this is what's on the line 35.

//to make a connection with database
$conn = mysql_connect("localhost", "root", "password") or die(mysql_error());


I don't know whether this is the problem or the code I'm writing.
I have searched for every possible answer but it is not what I was looking for.

this is my code (if the problem is not really on the line 35)


//validation error flag
$errflag = false;

//Input Validation
if($_POST['uname'] == '')
{
$errmsg_arr[]='Login ID missing';
$errflag = true;
}
if($_POST['pword'] == '')
{
$errmsg_arr[] = 'Password missing';
$errflag = true;
}


//if there are input validations, redirect back to the login form
if($errflag)
{
$_SESSION['ERRMSG_ARR'] = $errmsg_arr;
session_write_close();
header("location: login.php");
exit();
}

//to make a connection with database
$conn = mysql_connect("localhost", "root", "password") or die(mysql_error());


//to select the targeted database
mysql_select_db("ngchoonching", $conn) or die(mysql_error());

//to create a query to be executed in sql
$username = $_POST['uname'];
$password = $_POST['pword'];
$query = "SELECT * FROM profile WHERE username = '$username' AND password = '$password'";

//to run sql query in database
$result= mysql_query($query, $conn) or die(mysql_error());

//check whether the query was successful or not
if(isset($result))
{
if(mysql_num_rows($result) == 1)
{
//Login successful
session_regenerate_id();
$member = mysql_fetch_assoc($result);
$_SESSION['SESS_MEMBER_ID'] = $member['id'];
$_SESSION['SESS_FIRST_NAME'] = $member['firstname'];
$_SESSION['SESS_LAST_NAME'] = $member['lastname'];
$_SESSION['STATUS'] = true;
session_write_close();
header("location: login-successful.php");
exit();
}
else
{
//login failed
header("location: login-failed.html");
exit();
}
}
else
{
die("Query failed");
}

?>


I use localhost,phpmyadmin,xampp and I don't understand why the access is denied.

Answer

try $conn = mysql_connect("localhost", "root") or $conn = mysql_connect("localhost", "root", "")