PKM357 - 10 months ago 31

Java Question

I'm an intro Java student, and I'm studying for a final exam. I'm going over a prior quiz on repetition statement loops, and see an answer I got wrong and cannot figure out for the life of me why the answer is the way it is.

Can someone please tell me why

`z = 29`

`25`

`29`

`int z = 0;`

for(int x=0; x<5;x++){

for(int y=0; y<5;y++){

z++;

}

z++;

}

z--;

The only way I was able to get

`29`

`5`

`5*5=25`

`system.out.println(z);`

`4`

8

12

16

20

(so I'm now fairly confused) Any assistance you could provide would be greatly appreciated.

Answer

Your code fragment:

```
int z = 0;
for(int x=0; x<5;x++){
for(int y=0; y<5;y++){
z++;
}
z++;
}
z--;
```

Indeed results in `z`

being equal to `29`

. Lets calculate the difference for `z`

for each part. The inner `for`

loop iterates five times for each iteration of the outer loop so:

```
for(int y=0; y<5;y++){
z++;
}
```

is basically equal to:

```
z += 5;
```

We thus rewrite the program to:

int z = 0; for(int x=0; x<5;x++){z += 5;z++; } z--;

Now `z += 5;`

and `z++`

is equal to `z += 6;`

. We rewrite the program to:

int z = 0; for(int x=0; x<5;x++){z += 6;} z--;

The `for`

loop is again repeated five times so the update for `z`

is: `z += 5*6;`

or `z += 30;`

. We rewrite the program to:

int z = 0;z += 30;z--;

Finally we merge the three statements into one: `int z = 0+30-1;`

or

int z =29;