Is it possible to pass import a module with some parameter in python ?
All I mean by parameter is that there exists a variable in the module which is not initialized in that module, still I am using that variable in that module. In short, I want behaviour similar to function but unlike function, I want the variables of module to be exposed in the calling code.
#lists like data, count, prob_distribution are constructed from training_pool (not initialized in this file)
x = pymc.Uniform('x', lower = 0, upper = 1)
rv = [ Multinomial("rv"+str(i), count[i], prob_distribution[i], value = data[i], observed=True) for i in xrange(0, len(count)) ]
import a #I want some way tr pass value of training_pool
m = pymc.MCMC(a)
As @otus already answered, there is no way to pass parameters to modules.
I think you are following some of the introductory examples for PyMC2, which use a pattern where a module wraps all the code for the nodes in a Bayesian model. This approach is good for getting started, but, as you have found, can be limiting, when you want to run your model with a range of variations.
Fortunately, PyMC2 can create an MCMC object from a list or a dictionary as well as a module. What I recommend in this case is just what @oleg-s suggested in the comments: use a function. You can end the function with
return locals() to get a dictionary of everything that would have been in the module, and this is suitable input to the
pymc.MCMC constructor. Here is an example:
# a.py from pymc import * count = [10, 10] # perhaps good to put this stuff in data.py prob_distribution = [[.5, .5], [.1, .2, .7]] data = [[2, 8], [2, 3, 5]] def model(training_pool): x = Uniform('x', lower = 0, upper = 1) rv = [ Multinomial("rv"+str(i), count[i], prob_distribution[i], value = data[i], observed=True) for i in training_pool ] return locals()
# b.py import pymc, a training_pool =  m = pymc.MCMC(a.model(training_pool))