thomascirca - 7 months ago 45

C Question

I've been dabbling around a bit with C and I find that being able to directly manipulate bits is fascinating and powerful (and dangerous I suppose). I was curious as to what the best way would be to compare different bits in C would be. For instance, the number 15 is represented in binary as:

`00001111`

And the number 13 is represented as:

`00001101`

How would you compare what bits are different without counting them? It would be easy to use shifts to determine that 15 contains 4 1s and 13 contains 3 1s, but how would you output the difference between the two (ex that the 2^1 spot is different between the two)? I just can't think of an easy way to do this. Any pointers would be much appreciated!

EDIT: I should have clarified that I know XOR is the right way to go about this problem, but I had an issue with implementation. I guess my issue was comparing one bit at a time (and not generating the difference per say). The solution I came up with is:

`void compare(int vector1, int vector2) {`

int count = 0;

unsigned int xor = vector1 ^ vector2;

while (count < bit_length) {

if (xor % 2 == 1) { //would indicicate a difference

printf("%d ", count);

}

xor >>= 1;

count++;

}

}

Answer

Use bitwise operations:

```
c = a ^ b ;
00000010b = 00001111b ^ 00001101b;
```

What `^`

, or XOR, does is:

```
0 ^ 0 = 0
1 ^ 0 = 1
0 ^ 1 = 1
1 ^ 1 = 0
```

One way of thinking about it would be:

If the two operands (

`a`

and`b`

) are different, the result is`1`

.

If they are equal, the result is`0`

.

Source (Stackoverflow)