Alex - 1 month ago 4x

Python Question

I have a numpy array with the following shape:

`shape -> data`

5x3 -> [[

12 10 33

9 88 41

13 39 27

1 4 7

65 78 13

]]

I need the numpy array to look like this though:

`shape -> data`

5x3 -> [[

12 41 4

10 13 7

33 39 65

9 27 78

88 1 13

]]

Essentially, given a numpy array X, I want to create a new array, Y with the same shape as X that takes all the values (left -> right) in each column of X and then puts those values in the same order, but by row.

I have a feeling this might be a simple or easy thing to do with reshape, but I haven't been able to find out if its doable.

Answer

It's a simple enough procedure. We just need to perform two phases, a reshape and a transpose:

```
Y = X.reshape(X.shape[::-1]).T
```

Source (Stackoverflow)

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