Michael A Michael A - 2 months ago 9
Java Question

Transformation of multiple input files

Right now i am using this java (which receives one xml file parameter) method to perform XSLT transformation:

static public byte[] simpleTransform(byte[] sourcebytes, int ref_id) {
try {
StreamSource xmlSource = new StreamSource(new ByteArrayInputStream(sourcebytes));
StringWriter writer = new StringWriter();
transformations_list.get(ref_id).transformer.transform(xmlSource, new StreamResult(writer));
return writer.toString().getBytes("UTF-8");
} catch (Exception e) {
return new byte[0];

And in my xslt file i am using the
to refer to other transform related files.

I want to use my Java like this (get multiple xml files):

static public byte[] simpleTransform(byte[] f1, byte[] f2, byte[] f3, int ref_id)

An in my XSLT i don't want to call
but refer to the object by using f2 received in my Java method.

Is there a way to do it? how do i refer to


in my XSLT using this way?


I'm not entirely sure what is in f1, f2 etc. Is it the URL of a document? or the XML document content itself?

There are two possible approaches you could consider.

One is to write a URIResolver. When you call document('f2.xml') Saxon will call your URIResolver to get the relevant document as a Source object. Your URIResolver could return a StreamSource initialized with a ByteArrayInputStream referring to the relevant btye[] value.

A second approach is to supply the documents as parameters to the stylesheet. You could declare a global parameter <xsl:param name="f2" as="document-node()"/> and then use Transfomer.setParameter() to supply the actual document; within the stylesheet, replace document('f2.xml') by $f2. Saxon will accept a Source object as the value supplied to setParameter, so you could again create a StreamSource initialized with a ByteArrayInputStream referring to the relevant btye[] value; alternatively (and perhaps better) you could pre-build the tree by calling a Saxon DocumentBuilder.