user7189426 - 1 year ago 69
R Question

# compute mean of some entries of a matrix in R

I have a matrix of two columns. Some entries of column x are same, for example,

x[7]==x[8]== -0.11, x[14]==x[15]==x[16]==x[17]==0.01.

My question is: if the entries of column x are same, how can I compute the mean of their corresponding entries of v? and keep only one x and their mean of entries of v in the matrix? For example, for x[7] and x[8], their corresponding mean of v = mean(v[7]+v[8]). I need keep one -0.11 and the corresponding mean in the matrix.

``````           x          v
[1,]  -0.22 2.575144e-02
[2,]  -0.21 1.991324e-01
[3,]  -0.15 7.737715e-02
[4,]  -0.15 2.470678e-02
[5,]  -0.13 2.135258e-01
[6,]  -0.12 1.252464e-01
[7,]  -0.11 1.667752e-01
[8,]  -0.11 9.163501e-03
[9,]  -0.10 2.191712e-01
[10,] -0.08 1.974091e-02
[11,] -0.02 1.362226e-01
[12,] -0.01 1.623944e-04
[13,] -0.01 1.497634e-02
[14,]  0.01 1.811620e-02
[15,]  0.01 1.222637e-02
[16,]  0.01 1.668605e-02
[17,]  0.01 6.495694e-02
[18,]  0.03 2.702536e-03
[19,]  0.03 5.727469e-02
``````

Thanks!

What we are doing here is, just group by "x", and then take the mean of corresponding "v".

``````library(data.table)
setDT(dt)[, mean(v),by = "x"]
#         x          V1
#  1: -0.22 0.025751440
#  2: -0.21 0.199132400
#  3: -0.15 0.051041965
#  4: -0.13 0.213525800
#  5: -0.12 0.125246400
#  6: -0.11 0.087969351
#  7: -0.10 0.219171200
#  8: -0.08 0.019740910
#  9: -0.02 0.136222600
# 10: -0.01 0.007569367
# 11:  0.01 0.027996390
# 12:  0.03 0.029988613
``````
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