Joseph Joseph - 2 years ago 103
Javascript Question

Zebra stripes ignoring hidden elements

Say I have a table whose rows can be dynamically assigned

classes. Rows with that class are hidden via CSS. The rows are also styled with alternating colours, like so:

tr:nth-child(even) {
background-color: $light-grey;

However, I want every even, unhidden row to be shaded. So hidden rows are not counted when
is applied, and the pattern appears consistent. The following is my immediate attempt, but it doesn't do what I'm hoping for.

tr:not(.hidden):nth-child(even) {
background-color: $light-grey;

is simply referring to the rows' original indices, not the current selection scope from
. The two are simply 'filtered through' on top of one another.

Is there a
(or simply
) meta class in CSS? Are there any equivalents or alternate methods?

Or must I resort to Javascript?

(I should say that I can also use jQuery)

Answer Source

There is no way to do this in pure CSS as adding display:none or visibility:none doesn't remove the elements from the DOM, which is what CSS uses.

As a result, you will need to add a little JavaScript (which runs once the page has loaded) to do this, like so

var trs = document.getElementsByTagName("tr"), // Select whichever ones you need
    count = 0; // Counter for the non-hidden ones

for(var i = 0; i < trs.length; i++) {    
    if(!trs[i].classList.contains("hidden") && (count++)%2 == 0) { // Odd ones
        trs[i].style.background = "black";
    } else if(!trs[i].classList.contains("hidden")) { // Even ones
        trs[i].style.background = "lightgrey";
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