James Parker - 1 year ago 96

Java Question

I am not sure if I am using explicit type cast for the floating-point division in option 4 (Division). I need a little help understanding what is floating-point division.

I must use integers to store the 2 operands, a double to store the result. You must use an explicit type cast for the floating-point division in option 4. Also use a switch statement to process the menu choices. After each computation

`import java.util.Scanner;`

public class SimpleCalculator

{

//-----------------------------------------------------------------

// Calculates two integers

// using values entered by the user.

//-----------------------------------------------------------------

public static void main(String[] args)

{

//Variables

final int ADDITION = 1,SUBTRACTION = 2, MULTIPLICATION = 3,DIVISION = 4, EXIT = 5;

int num1 = 0, num2 = 0, choice = 0;

double dblNum1, dblNum2, result;

String equation = "";

do

{

//Processing

equation = "";

Scanner scan = new Scanner(System.in);

System.out.println("Choose from the following: ");

System.out.println("1. Add 2 integers");

System.out.println("2. Subtract 2 integers");

System.out.println("3. Multiply 2 integers");

System.out.println("4. Divide 2 integers");

System.out.println("5. Exit");

System.out.print("Enter choice: ");

choice = scan.nextInt();

if(choice < 5 && choice > 0)//keeps program from asking for two numbers if exiting

{

System.out.print("Enter first integer: ");

num1 = scan.nextInt();

System.out.print("Enter second integer: ");

num2 = scan.nextInt();

}

//switch for operations

switch (choice)

{

case ADDITION:

result = num1 + num2;

equation = ((num1) + " + " + (num2) + " = "+ result);

break;

case SUBTRACTION:

result = num1 - num2;

equation = ((num1) + " - " + (num2) + " = "+ result);

break;

case MULTIPLICATION:

result = num1 * num2;

equation = ((num1) + " * " + (num2) + " = "+ result);

break;

case DIVISION:

if(num2 == 0)//when denominator becomes zero

{

System.out.println("DIVISION NOT POSSIBLE");

break;

}

dblNum1 = num1;//convert int to double

dblNum2 = num2;

result = dblNum1/dblNum2;

equation = ((num1) + "/" + (num2) + " = "+ result);

break;

case EXIT:

System.exit(0);

break;

default:

System.out.println("YOU HAVE ENTERED AN INCORRECT CHOICE");

}

//Output

System.out.println(equation);

System.out.println();

}while(choice != EXIT);

}

}

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Answer Source

No, that's not an explicit typecast. You would want to use something like this:

```
result = ((double) num1) / ((double) num2);
```

Actually, because of the widening rules for the `/`

operator, you would only need one of those explicit casts, but there's no harm in having both. In fact, because the cast operator `()`

has higher precedence than the division operator `/`

, you could write it as:

```
result = (double) num1 / num2;
```

which combines an explicit cast of the numerator and an implicit cast of the denominator.

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