Qinsi Qinsi - 2 years ago 133
Bash Question

How can I redirect stdout and stderr with variant?

Normally, we use

sh script.sh 1>t.log 2>t.err

to redirect log.

How can I use variant to log:

string="1>t.log 2>t.err"
sh script.sh $string

Answer Source

You need to use 'eval' shell builtin for this purpose. As per man page of bash command:

   eval [arg ...]
          The  args are read and concatenated together into a single command.  This command is then read and exe‐
          cuted by the shell, and its exit status is returned as the value of eval.  If there  are  no  args,  or
          only null arguments, eval returns 0.

Run your command like below:

eval sh script.sh $string

However, do you really need to run script.sh through sh command? If you instead put sh interpreter line (using #!/bin/sh as the first line in your shell script) in your script itself and give it execute permission, that would let you access return code of ls command. Below is an example of using sh and not using sh. Notice the difference in exit codes.

Note: I had only one file try.sh in my current directory. So ls command was bound to exit with return code 2.

$ ls try1.sh try1.sh.backup 1>out.txt 2>err.txt
$ echo $?

$ eval sh ls try1.sh try1.sh.backup 1>out.txt 2>err.txt
$ echo $?

In the second case, the exit code is of sh shell. In first case, the exit code is of ls command. You need to make cautious choice depending on your needs.

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