Greg Greg - 1 month ago 4x
C Question

Casting between sockaddr and sockaddr_in6

I've been reading Beej's Guide to Network Programming and in one of his examples, he casts a pointer to

struct sockaddr
to a
struct sockaddr_in6
pointer like shown below.

void *addr;
char *ipver;

// get the pointer to the address itself,
// different fields in IPv4 and IPv6:
if (p->ai_family == AF_INET) { // IPv4
struct sockaddr_in *ipv4 = (struct sockaddr_in *)p->ai_addr;
addr = &(ipv4->sin_addr);
ipver = "IPv4";
} else { // IPv6
struct sockaddr_in6 *ipv6 = (struct sockaddr_in6 *)p->ai_addr;
addr = &(ipv6->sin6_addr);
ipver = "IPv6";

How is this possible, since the sizes of the structs are different?


ai_family and ai_addr are fields of the addrinfo struct, so presumably the code you are quoting had called getaddrinfo() beforehand.

The result of getaddrinfo() is a NULL-terminated linked list of addrinfo structs, where the addrinfo::ai_addr field is a pointer to an allocated memory block that is of sufficient size to hold a socket address of the reported addrinfo::ai_family type. The size of the address is reported in the addrinfo::ai_addrlen field.

For AF_INET, the addrinfo::ai_addr field is pointing at a memory block containing a sockaddr_in struct.

For AF_INET6, the addrinfo::ai_addr field is pointing at a memory block containing a sockaddr_in6 struct.

That is why the type-casts work.

The addrinfo::ai_addr field is declared as struct sockaddr* so it can be passed as-is to the addr parameter of the bind() and connect() functions without type-casting. The addrinfo::ai_addrlen field can be passed as-is to their addrlen parameter.