Teererai Marange - 11 months ago 52

C++ Question

I have created a 2d array called digits and would like to initialize each of the subarrays one by one to make my code clearer. I understand that the following code works:

`string digits[2][5] = { { " - ","| |"," ","| |"," - " },{ " - ","| |"," ","| |"," - " } };`

But am wondering why the following doesn't work:

`string digits[2][5];`

digits[0] = { " - ","| |"," ","| |"," - " };

digits[1] = { " - ", "| |", " ", "| |", " - " };

Answer Source

The 2nd one is not initialization, it's assignment (of elements of `digits`

).

```
string digits[2][5]; // initialization
digits[0] = { " - ","| |"," ","| |"," - " }; // assignment of the 1st element of digits
digits[1] = { " - ", "| |", " ", "| |", " - " }; // assignment of the 2nd element of digits
```

The element of `digits`

is an array, the raw array can't be assigned as a whole.

Objects of array type cannot be modified as a whole: even though they are lvalues (e.g. an address of array can be taken), they cannot appear on the left hand side of an assignment operator

You could do this with `std::array`

or `std::vector`

, which could be assigned with braced initializer.

```
std::array<std::array<std::string, 5>, 2> digits;
digits[0] = { " - ","| |"," ","| |"," - " };
digits[1] = { " - ", "| |", " ", "| |", " - " };
```