Python Question
Perl regular expression \U
I am trying to convert some perl code to python. I came across this line
if($Var=~ /^\U/)
{ dosomething(); }
I have looked over the web for expression, but i am not able to comprehend its meaning.
\U uppercase till \E
\E end case modification
Please give an example of the correct usage if possible and how to approach for a python equivalent.
Answer
The regex engine knows nothing of \U. It's processed by the Perl parser in double quoted and regex literals.
"\Uabcdef" is the same as uc("abcdef")
"\Uabc\Edef" is the same as uc("abc")."def"
That means that
/^\Uabc/ is the same as /^ABC/
/^\U/ is the same as /^/
/^/ (and thus /^\U/) is rather pointless, as it will always match.
If you wanted to make sure a string consists entirely of upper case letters, you'd use /^\p{Lu}*\z/, or /^[A-Z]*\z/ if you have a very limited definition of letter.
Perl's
$var =~ /\Uabc\Edef/
would be written as follows in Python:
re.search("abc".upper() + "def", var)
Source (Stackoverflow)