Python Question
Printing numbers from 1-100 as words in Python 3
List_of_numbers1to19 = ['one', 'two', 'three', 'four', 'five', 'six', 'seven',
'eight', 'nine', 'ten', 'eleven', 'twelve', 'thirteen',
'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen',
'nineteen']
List_of_numbers1to9 = List_of_numbers1to19[0:9]
List_of_numberstens = ['twenty', 'thirty', 'fourty', 'fifty', 'sixty', 'seventy',
'eighty', 'ninety']
for i in List_of_numbers1to19:
print(i)
list_of_numbers21to99 = []
count = 19
tens_count = 0
for j in List_of_numberstens:
for k in List_of_numbers1to9:
if tens_count%10 == 0:
#should print an iteration of List_of_numberstens
tens_count +=1
tens_count +=1
print(j, k)
As you can see, this is getting messy :P So sorry for that.
Basically I'm trying to print them using three different for-loops with a different index. I have tried slicing the list and indexing the list, but I keep getting output for the numbers multipliable by 10 as the full list of
List_of_numberstensI think it's clear what I'm trying to do here.
Thanks in advance for your help!
Answer
I know you already accepted an answer, but you particularly mentioned nested loops - which it doesn't use - and you're missing what's great about Python's iteration and not needing to do that kind of i//10-2 and print(j,k) stuff to work out indexes into lists.
Python's for loop iteration runs over the items in the list directly and you can just print them, so I answer:
digits = ['one', 'two', 'three', 'four', 'five',
'six', 'seven', 'eight', 'nine']
teens = ['ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen',
'sixteen', 'seventeen', 'eighteen', 'nineteen']
tens = ['twenty', 'thirty', 'fourty', 'fifty',
'sixty', 'seventy', 'eighty', 'ninety']
for word in digits + teens:
print(word)
for tens_word in tens:
print(tens_word) # e.g. twenty
for digits_word in digits:
print(tens_word, digits_word) # e.g. twenty one
print("one hundred")
Source (Stackoverflow)