Nikita Sivukhin Nikita Sivukhin - 1 year ago 1601
Python Question

pandas.DataFrame corrwith() method

I recently start working with

. Can anyone explain me difference in behaviour of function

Suppose i have one

frame = pd.DataFrame(data={'a':[1,2,3], 'b':[-1,-2,-3], 'c':[10, -10, 10]})

And i want calculate correlation between features 'a' and all other features.
I can do it in the following way:

frame.drop(labels='a', axis=1).corrwith(frame['a'])

And result will be:

b -1.0
c 0.0

But very similar code:

frame.drop(labels='a', axis=1).corrwith(frame[['a']])

Generate absolutely different and unacceptable table:

a NaN
b NaN
c NaN

So, my question is: why in case of
as second argument we get such strange output?

Answer Source

What I think you're looking for:

Let's say your frame is:

frame = pd.DataFrame(np.random.rand(10, 6), columns=['cost', 'amount', 'day', 'month', 'is_sale', 'hour'])

You want the 'cost' and 'amount' columns to be correlated with all other columns in every combination.

focus_cols = ['cost', 'amount']

enter image description here

Answering what you asked:

Compute pairwise correlation between rows or columns of two DataFrame objects.


other : DataFrame

axis : {0 or ‘index’, 1 or ‘columns’},

default 0 0 or ‘index’ to compute column-wise, 1 or ‘columns’ for row-wise drop : boolean, default False Drop missing indices from result, default returns union of all Returns: correls : Series

corrwith is behaving similarly to add, sub, mul, div in that it expects to find a DataFrame or a Series being passed in other despite the documentation saying just DataFrame.

When other is a Series it broadcast that series and matches along the axis specified by axis, default is 0. This is why the following worked:

frame.drop(labels='a', axis=1).corrwith(frame.a)

b   -1.0
c    0.0
dtype: float64

When other is a DataFrame it will match the axis specified by axis and correlate each pair identified by the other axis. If we did:

frame.drop('a', axis=1).corrwith(frame.drop('b', axis=1))

a    NaN
b    NaN
c    1.0
dtype: float64

Only c was in common and only c had its correlation calculated.

In the case you specified:

frame.drop(labels='a', axis=1).corrwith(frame[['a']])

frame[['a']] is a DataFrame because of the [['a']] and now plays by the DataFrame rules in which its columns must match up with what its being correlated with. But you explicitly drop a from the first frame then correlate with a DataFrame with nothing but a. The result is NaN for every column.

Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download