NoNaMe NoNaMe - 1 year ago 36
Java Question

Issue with MD5 hash generation

I am using following code to generate MD5 Hash for my application it encodes some string value and then I send this generated hash through my web service to some .Net code, that code read my MD5 hash and generate MD5 of the string the strings he is getting from DB and then compare them

public static String getMD5Hash(String val) throws Exception {
byte[] bytes = val.getBytes();

MessageDigest m = MessageDigest.getInstance("MD5");
byte[] digest = m.digest(bytes);
String hash = new BigInteger(1, digest).toString(16);
return hash;

public static void main(String[] asd) throws Exception{
for(int i=0;i<10;i++){
System.out.println(getMD5Hash(i+Math.pow(10, i)+""));//for testing
System.out.println(getMD5Hash(i+""));//for testing

The issue is as i am getting converted hash from BigInteger and some times generated hash starts with a 0 in that case Biginteger does not consider that 0 and on the other side when .Net generates that hash of the same string it generate it with 0 and in this way string comparison return false, e-g
hash code i generate and send "
" where in .Net hash is "

also some times it generate code like

.Net generates 0012678D1922799CF9122B3F103975F1 and java 12678D1922799CF9122B3F103975F1


0002678D1922799CF9122B3F103975F1 and 2678D1922799CF9122B3F103975F1

How can i get this code with all 0s that are in start.
Thanks in advance.

Answer Source

This question has some better methods of generating the hex string:

In Java, how do I convert a byte array to a string of hex digits while keeping leading zeros?

Since you're already using BigInteger, this seems like the best solution:

BigInteger bi = new BigInteger(1, digest);
String hash = String.format("%0" + (digest.length << 1) + "X", bi);