screwnut screwnut - 1 year ago 90
C++ Question

C++11 Can I ensure a condition_variable.wait() won't miss a notification?

I have thread 1 executing the following code:

unique_lock<mutex> ul(m);
while(condition == true)

And thread 2 executing this code:

condition = false;

Unfortunately I'm hitting a timing issue:

T1: condition checks true
T2: condition set to false
T2: cv.notify_one()
T1: cv.wait()

Thread 1 misses the notification completely and remains blocked on wait(). I tried using the version of wait() which takes a predicate but with essentially the same result. That is, the body of the predicate performs the check, but before it returns, the condition's value is changed and the notification is sent. The predicate then returns.

How can I fix this?

Answer Source

You should fix this race condition by having thread 2 lock the condition's mutex before changing the flag.

You are describing a typical race condition that happens for unprotected flags and conditions. These race conditions are the reason for the mutex lock pattern in condition usage. Put simply, always have a mutex protect the variables involved in checking a condition value.

In code for thread 2:

unique_lock<mutex> ul(m);
condition = false;
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