Paolo Forgia Paolo Forgia - 1 year ago 46
Java Question

Curly braces only method in Java

Why does Java accept a brackets only method? What is made for?

{
// Do something
}


I also noticed that it is executed automatically after the static-block but before the constructor. Although the constructor of the super class is executed before.

Is there a specific reason for this order?

This is the JUnit I made for discovering the execution order:

public class TestClass extends TestSuperClass {

public TestClass() {
System.out.println("constructor");
}

@Test
public void test() {
System.out.println("test");
}

{
System.out.println("brackets");
}

static {
System.out.println("static");
}
}





public class TestSuperClass {

public TestSuperClass() {
System.out.println("super class constructor");
}

{
System.out.println("super class brackets");
}

static {
System.out.println("super class static");
}
}


As output I get:

super class static
static
super class brackets
super class constructor
brackets
constructor
test

Answer Source

It is the same as static block but just not static. So it will execute in the order that you already found out - after super constructor but before constructor. However, if static-block can be useful regular block not so much. So it is never used, but it is legal. I never saw it used and can not think of any particular purpose, but it is part of valid syntax. If it was not then static block wouldn't be either.

Recommended from our users: Dynamic Network Monitoring from WhatsUp Gold from IPSwitch. Free Download