shahalpk shahalpk - 1 year ago 315
PHP Question

Laravel validator `required` fails for empty string also

I'm trying laravel

validator in my code, unfortunately it fails for even empty string. I do not want it fail for empty string.

$validator = \Validator::make(array("name"=>""), array("name"=>"required"));
if ($validator->fails()){
} else {
die("no errors :)");

It gives me the following output

protected 'messages' =>
array (size=1)
'name' =>
array (size=1)
0 => string 'The name field is required.' (length=27)
protected 'format' => string ':message' (length=8)

It is supposed to pass, since i'm giving an empty string as the

The above behavior happens in OSX environment (PHP Version 5.5.18), but it works fine in linux environment (PHP Version 5.5.9-1ubuntu4.5).

Answer Source

The required rule actually returns false if you pass an empty string.

If we look at the code (Illuminate\Validation\Validator)

protected function validateRequired($attribute, $value)
    if (is_null($value))
        return false;
    elseif (is_string($value) && trim($value) === '')
        return false;

    // [...]

    return true;

I think your only option here is to write your own validation rule that checks if the value is not null:

Validator::extendImplicit('attribute_exists', function($attribute, $value, $parameters){
    return ! is_null($value);

(The extendImplicit is needed because with extend custom rules will only run when the value is not an empty string)

And then use it like this:

\Validator::make(array("name"=>""), array("name"=>"attribute_exists"));
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