NaturalBornCamper NaturalBornCamper - 5 months ago 16x
PHP Question

Find the 4 coordinates of a rotated transparent rectangle in png image

I didn't find anything about the subject, but I am dreaming vividly or is it possible in PHP to scan a PNG image and find the transparent positions in a picture?

for example, if there is a image of a TV with a transparent hole where the screen is. Can I find the most top-left, most top-right, most bottom-left, most bottom-right coordinates of transparent pixels by scanning the alpha-channel?

Not sure if there's a library doing this, I checked real quick but did not find..


Maybe not the most elegant solution and I'm sure there's a better way of doing it, but this works for a well-formed png image

// Returns the coordinates of a transparent rectangle in a PNG file (top left, top right, lower left, lower right
public function getTransparentRectangleCoordinates($fileUrl)
    define ('TRANSPARENCY_THRESHOLD', 100); // 127=fully transparent, 0=black

    $img = @imagecreatefrompng($fileUrl);

    if (!$img) return ('Invalid PNG Image');

    $coordLowestX = array(imagesx($img), '');
    $coordHighestX = array(0, '');
    $coordLowestY = array('', imagesy($img));
    $coordHighestY = array('', 0);

    $minX = imagesx($img);
    $maxX = 0;
    $minY = imagesy($img);
    $maxY = 0;

    // Scanning image pixels to find transparent points
    for ($x=0; $x < imagesx($img); ++$x)
        for ($y=0; $y < imagesy($img); ++$y)
            $alpha = (imagecolorat($img, $x, $y) >> 24) & 0xFF;
            if ($alpha >= TRANSPARENCY_THRESHOLD)
                if ($x < $coordLowestX[0]) $coordLowestX = array($x, $y);
                if ($x > $coordHighestX[0]) $coordHighestX = array($x, $y);
                if ($y < $coordLowestY[1]) $coordLowestY = array($x, $y);
                if ($y >= $coordHighestY[1]) $coordHighestY = array($x, $y);

                if ($x < $minX) $minX = $x;
                if ($x > $maxX) $maxX = $x;

                if ($y < $minY) $minY = $y;
                if ($y > $maxY) $maxY = $y;

    // This means it's a non-rotated rectangle
    if ( $coordLowestX == array($minX, $minY) )
        $isRotated = false;

        return array( array($minX, $minY), array($maxX, $minY), array($minX, $maxY), array($maxX, $maxY) );
    // This means it's a rotated rectangle
        $isRotated = true;

        // Rotated counter-clockwise
        if ($coordLowestX[1] < $coordHighestX[1])
            return array($coordLowestX, $coordLowestY, $coordHighestY, $coordHighestX);
        else // Rotated clockwise
            return array($coordLowestY, $coordHighestY, $coordLowestX, $coordHighestX);