Are functions passed parameters enclosed in parentheses because they are handled as tuples, or just a result of f(x) convention?
i.e. is (b, a, r) a tuple here:
def foo(b, a, r):
>>> 3 * 2 + 1
>>> 3 * (2 + 1)
You can answer this by looking at the Python Grammar.
The relevant lines are:
funcdef: 'def' NAME parameters ['->' test] ':' suite parameters: '(' [typedargslist] ')'
So in your example, the grammar would say that
(b, a, r) is a
typedargslist surrounded by brackets.