Raaj - 18 days ago 5x

C++ Question

I'm noticing a very peculiar thing.

After going through this lecture, I implemented some code for heap-sort in C++.

The code is below.

`template<typename T> void min_heapify(std::vector<T> &vec, int i, int size)`

{

int left = (2*i); //left child of a zero-indexed heap (array)

int right = (2*i)+1; //right child.

int min;

min = ( (left<size) && (vec[left] < vec[i]) ) ? left : i;

min = ( (right<size) && (vec[right] < vec[min]) ) ? right : min;

if (min!= i)

{

swapper(vec[i],vec[min]);

min_heapify(vec, min, size);

}

}

template<typename T> void build_min_heap(std::vector<T> &vec, int size)

{

int i = size/2;

while(i--)

{

min_heapify(vec, i, size);

}

}

template<typename T> void heap_sort(std::vector<T> &vec, int size)

{

// build min heap

build_min_heap(vec, size);

// then extract min repeatedly.

while(size>0)

{

size--;

swapper(vec[0],vec[size]);

min_heapify(vec,0,size);

}

}

int main()

{

vector<int> v{14,-1,1000, -999, 3,2,5,10};

heap_sort(v, v.size());

return 0;

}

The peculiar thing is that it makes sense to me that

- build a min heap

- extract min (or executing min-heapify at the root after building a min heap)

should result in

However, after executing this code and printing out the resultant vector,

I get :

`1000 14 10 5 3 2 -1 -999`

while trying to make sense of what is going on, I changed

`min = ( (left<size) && (vec[left] < vec[i]) ) ? left : i;`

min = ( (right<size) && (vec[right] < vec[min]) ) ? right : min;

to

`min = ( (left<size) && (vec[left] > vec[i]) ) ? left : i;`

min = ( (right<size) && (vec[right] > vec[min]) ) ? right : min;

which actually ends up selecting the bigger(or maximum) of the parent and child nodes, and the resultant vector is :

`-999 -1 2 3 5 10 14 1000`

Am I doing something wrong or is my understanding of heap/heap sort unclear? What am I missing here?

Answer

Yes the `swapper(vec[0],vec[size]);`

is the extraction.
You are extracting the first element into the last element of the vector. Hence getting the opposite result.

The heaps min element is `vec[0]`

. Swapping that to the last position will create a max to min ordering within that vector.

If you implement something like

```
result.push_back(heap.pop_min());
```

You will get the ordering you were expecting.

Source (Stackoverflow)

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