roxid - 5 months ago 56

C Question

Got confused with the following peice of code.

`#include <stdio.h>`

void main()

{

int a=0100;

printf("%x",a);

}

The value I am getting is 40.

Can someone explain me whats going on here?

Note : When I removed the digit 0 before digit 1 then its coming 64 which is correct, when 100 is converted into hex.

Codepad link to above code

Answer

In C, a constant prefixed with a `0`

is an **octal** constant. 0100 in base 8 is
1000000 in base 2, which is 40 in hexadecimal, which is 64 in base 10. So your program is printing exactly what it should.