Ratikanta Patra Ratikanta Patra - 1 year ago 130
Swift Question

Strange behavior of Swift

While playing around with Swift I came across the following scenario:

let testVar: String = "random string"
var myVar: Int! = 0
myVar = Int(testVar)
print("myVar = \(myVar)")


myVar = nil

Since I have used
mark before
, isn't it supposed to contain non-nil values all the time?
How come
Here is the screenshot of my playground code:


Answer Source

The '!' indicates forced unwrapping of an optional. However it's type is still optional and therefore can be nil.

(You're just telling the compiler that you guarantee it won't become nil.)

A line like...

let v: Int = myVar

...at the end of your code will get you the crash you expect.

Another example is the way outlets are handled. They are typically defined such as:

@IBOutlet weak var detailDescriptionLabel: UILabel!

Before viewDidLoad is called, it is nil. Again, the '!' is just a promise to the compiler that it won't be used until it contains a valid reference.

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