Alec Holmes Alec Holmes - 7 days ago 5
Java Question

Java xsd validation of xml without namespace

I want to validate an XML file against an XSD schema. The XML files root element does not have any namespace or xsi details. It has no attributes so just

<root>
.

I have tried the following code from http://www.ibm.com/developerworks/xml/library/x-javaxmlvalidapi.html with no luck as I receive
cvc-elt.1: Cannot find the declaration of element 'root'


SchemaFactory factory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema");

File schemaFile = new File("schema.xsd");

Schema xsdScheme = factory.newSchema(schemaFile);

Validator validator = xsdScheme.newValidator();

Source source = new StreamSource(xmlfile);

validator.validate(source);


The xml validates fine with the namespace headers included etc (added via xmlspy), but I would have thought the xml namespace could be declared without having to manually edit the source file?

Edit and Solution:

public static void validateAgainstXSD(File file) {

try {
SchemaFactory factory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema");

File schemaFile = new File("path/to/xsd");

Schema xsdScheme = factory.newSchema(schemaFile);

Validator validator = xsdScheme.newValidator();

SAXSource source = new SAXSource(
new NamespaceFilter(XMLReaderFactory.createXMLReader()),
new InputSource(new FileInputStream(file)));

validator.validate(source,null);

} catch (Exception e) {
e.printStackTrace();
}

}

protected static class NamespaceFilter extends XMLFilterImpl {

String requiredNamespace = "namespace";

public NamespaceFilter(XMLReader parent) {
super(parent);
}

@Override
public void startElement(String arg0, String arg1, String arg2, Attributes arg3) throws SAXException {
if(!arg0.equals(requiredNamespace))
arg0 = requiredNamespace;
super.startElement(arg0, arg1, arg2, arg3);
}
}

Answer

You have two separate concerns you need to take care of:

  1. Declaring the namespace that your document uses.
  2. Putting an xsi:schemaLocation attribute in the file to give a hint (!) where the schema is.

You can safely skip the second part, as the location is really only a hint. You cannot skip the first part. The namespace declared in the XML file is matched against the schema. Important, this:

<xml> ... </xml>

Is not the same as this:

<xml xmlns="urn:foo"> ... </xml>

So you need to declare your namespace in the XML document, otherwise it will not correspond to your schema and you will get this error.

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