Error doing a compound if condition with integers in Bash

Question

I am trying to perform a OR operation between two sub AND conditions like as follows.

elif [[ $RBIT >= 7000.00 && $RBIT <= 15000.00 ]] || [[ $TBIT >= 7000.00 && $TBIT <= 15000.00 ]]; then

echo #statements;

exit 0;

fi

But getting it in error.

/script: line 20: syntax error in conditional expression

/script: line 20: syntax error near `7000.00'

/script: line 20: `elif [[ $RBIT >= 7000.00 && $RBIT <= 15000.00 ]] || [[ $TBIT >= 7000.00 && $TBIT <= 15000.00 ]]; then'

Of course, the variables RBIT and TBIT has float values with 2 decimal points.

I am confused if I caused a syntax error here or 'if condition' doesn't work like that way. Kindly help.

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Answer 1

Bash supports only integer math. So, you could rewrite your condition as:

elif ((RBIT >= 7000 && RBIT <= 15000)) || ((TBIT >= 7000 && TBIT <= 15000)); then

While dealing with integers, ((...)) is a better construct to use. And $ is optional for variable expansion inside ((...)) expression.

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Error doing a compound if condition with integers in Bash

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