Uwe Uwe - 1 year ago 113
MySQL Question

Reformat MySQL date with PHP

I want to select data from a MySQL database and show it in a table, which is working so far, but I have a problem with the date format.

I want to reformat the MySQL Date to dd/mm/YY but I don't know how to do it because I don't specifically select the date column. I just select all columns from the table.


echo "<table style='border: solid 1px black;'>";
echo "<tr><th>Id</th><th>Name</th><th>Date</th></tr>";

class TableRows extends RecursiveIteratorIterator {
function __construct($it) {
parent::__construct($it, self::LEAVES_ONLY);

function current() {
return "<td style='width: 150px; border: 1px solid black;'>" . parent::current(). "</td>";

function beginChildren() {
echo "<tr>";

function endChildren() {
echo "</tr>" . "\n";

$servername = "";
$username = "";
$password = "";
$dbname = "";

try {
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
$stmt = $conn->prepare("SELECT * FROM users");

$result = $stmt->setFetchMode(PDO::FETCH_ASSOC);

foreach(new TableRows(new RecursiveArrayIterator($stmt->fetchAll())) as $k=>$v) {
echo $v;
catch(PDOException $e) {
echo "Error: " . $e->getMessage();
$conn = null;
echo "</table>";

Answer Source

Isn't it that $k is the column name and $v is the value?

If yes, then you can easily detect the date column values and format them:

 foreach(new TableRows(new RecursiveArrayIterator($stmt->fetchAll())) as $k=>$v) { 
     switch ($k) {
          case 'date_column':
                // echo formatted $v
                echo $v;
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