HTML Question
JavaScript: show password on hold
I have 2 inputs for passwords. Each input field has 'show' button, which shows password on holding that button.
<form name="resetting_form" method="post" action="">
<div class="form-group has-feedback">
<input type="password" id="password_first" required="required" placeholder="New Password" class="form-control">
<span class="show">show</span>
</div>
<div class="form-group has-feedback">
<input type="password" id="password_second" required="required" placeholder="Repeat Password" class="form-control">
<span class="show">show</span>
</div>
<input type="submit" class="btn btn-primary" value="Submit">
</form>
Here is what I have
$(".form-control").on("keyup",function(){
if ($(this).val())
$(".show").show();
else
$(".show").hide();
});
$(".show").mousedown(function(){
$(".form-control").attr('type','text');
}).mouseup(function(){
$(".form-control").attr('type','password');
}).mouseout(function(){
$(".form-control").attr('type','password');
});
Problem
When I click to 'show' button, both input fields are shown. How to make sure that only corresponding password is shown?
Answer Source
When you use $(".form-control"), jquery select all .form-control element. But you need to select target element using this variable in event function and use .prev() to select previous element.
$(".show").mousedown(function(){
$(this).prev().attr('type','text');
}).mouseup(function(){
$(this).prev().attr('type','password');
}).mouseout(function(){
$(this).prev().attr('type','password');
});