SuperMan - 25 days ago 5x

C Question

Find the maximum of two numbers. You should not use if-else or any other comparison operator. I found this question on online bulletin board, so i thought i should ask in StackOverflow

EXAMPLE

Input: 5, 10

Output: 10

I found this solution, can someone help me understand these lines of code

`int getMax(int a, int b) {`

int c = a - b;

int k = (c >> 31) & 0x1;

int max = a - k * c;

return max;

}

Answer

```
int getMax(int a, int b) {
int c = a - b;
int k = (c >> 31) & 0x1;
int max = a - k * c;
return max;
}
```

Let's dissect this. This first line is straightforward - it stores the difference of `a`

and `b`

. This value is negative if `a < b`

and is nonnegative otherwise.

In the next line:

```
int k = (c >> 31) & 0x1;
```

the idea is to check if the value of `c`

is negative. In virtually all modern computers, numbers are stored in a format called *two's complement* in which the highest bit of the number is 0 if the number is positive and 1 if the number is negative. Moreover, most ints are 32 bits. `(c >> 31)`

shifts the number down 31 bits, leaving the highest bit of the number in the spot for the lowest bit. The next step of taking this number and ANDing it with 1 (whose binary representation is 0 everywhere except the last bit) erases all the higher bits and just gives you the lowest bit. Since the lowest bit of `c >> 31`

is the highest bit of `c`

, this reads the highest bit of `c`

as either 0 or 1. Since the highest bit is 1 iff `c`

is 1, this is a way of checking whether `c`

is negative (1) or positive (0). Combining this reasoning with the above, `k`

is 1 if `a < b`

and is 0 otherwise.

The final step is to do this:

```
int max = a - k * c;
```

If `a < b`

, then `k == 1`

and `k * c = c = a - b`

, and so

```
a - k * c = a - (a - b) = a - a + b = b
```

Which is the correct max, since `a < b`

. Otherwise, if `a >= b`

, then `k == 0`

and

```
a - k * c = a - 0 = a
```

Which is also the correct max.

Source (Stackoverflow)

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