Abdellah Didi - 7 months ago 39
Python Question

# Sum All elements of each array in an array of array

I have this dictionary:

``````import numpy as np
dct={'W1': np.array([[ 1.62434536, -0.61175641, -0.52817175],
[-1.07296862,  0.86540763, -2.3015387 ]]),
'b1': np.array([[ 1.74481176],
[-0.7612069 ]]),
'W2': np.array([[ 0.3190391 , -0.24937038],
[ 1.46210794, -2.06014071],
[-0.3224172 , -0.38405435]]),
'b2': np.array([[ 1.13376944],
[-1.09989127],
[-0.17242821]]),
'W3': np.array([[-0.87785842,  0.04221375,  0.58281521]]),
'b3': np.array([[-1.10061918]])}
``````

I need to sum all the elements of W1, W2, W3 after squared them, each one at a time then all of the three.

I used this to extract a list with the keys W(i)

``````l=[v for k, v in dict.items() if 'W' in k]
``````

How could I get the sum of the squared elements in each array?
When taken each array separately I do:

`````` np.sum(np.square(l[0]) to get 10.4889815722 for l[0]
``````

I don't know though how to them all in one shot

``````>>> import numpy as np