AJ Riley - 1 year ago 118

Vb.net Question

"Write a program which reads in a start and an end value. The program then stores all the even numbers between these two values (inclusive) in an array. The user is then asked to select a number (n), the program should output the nth even number"

`Private Sub Button1_Click(sender As System.Object, e As System.EventArgs) Handles Button1.Click`

number1 = InputBox("Enter first number")

number2 = InputBox("enter second number")

Any guidance on this would be much appreciated, I'm completely lost.

Recommended for you: Get network issues from **WhatsUp Gold**. **Not end users.**

Answer Source

Ok, the edit is making more sense to me now. You were on the right track getting the first three inputs. Then we neeed to do 2 things to our inputs:

1) Get the even numbers within the range the user has given us

2) Return the nth term if it exists

I would approach the problem like this:

```
'Get our inputs
Dim number1 As Integer = CInt(InputBox("Enter first number"))
Dim number2 As Integer = CInt(InputBox("Enter second number"))
Dim nthTerm As Integer = CInt(InputBox("Enter Nth Term"))
Dim evenNumbers As New List(Of Integer)
'Now, we want to get a list of all the even numbers within n1 to n2 range
For i As Integer = number1 To number2
'if the number divided by 2 has a remainder of 0, then it's an even number
If i Mod 2 = 0 Then evenNumbers.Add(i)
Next
'Now that we have all the even #s, try to return the nth one as long as it exists
Try
'We substract 1 from the nthTerm entered by used to account for list's 0-based index
MsgBox(evenNumbers(nthTerm - 1).ToString)
Catch ex As Exception
MsgBox("Nth Term out of bounds")
End Try
```

Recommended from our users: **Dynamic Network Monitoring from WhatsUp Gold from IPSwitch**. ** Free Download**