user3797489 user3797489 - 3 months ago 9
C Question

getting wrong answer in pattern printing program

I have written the code to print a pattern in C. My expected answer is very different from the one that I am getting .I am very new to C language. I have debugged the code but unable to find the error. Please help me in finding the error. My code is as follows.

#include <stdio.h>

int main()
{
//code
int T,i,j;

scanf("%d",&T);

while(T--)
{
char str[5];
for(i=0;i<5;i++)
{
scanf("%c",&str[i]);
}
printf("\n");

for(j=1;j<=5;j++)
{
for(i=0;i<5-j;i++)
{
printf(".");
}
for(i=0;i<j;i++)
{
printf("%c",str[i]);
}
}
printf("\n");
}
return 0;
}


The input to the program is as follows:

Input:

1
geeks


The expected output of the program is as follows:

Expected output:

....g
...ge
..gee
.geek
geeks


The actual output of the program is as follows:

Actual output:

....
...
g..
ge.
gee

LPs LPs
Answer

Correcting your bad code

#include <stdio.h>

int main()
{
    //code
    int T,i,j;

    scanf("%d",&T);

    while(T--)
    {
        char str[5];
        for(i=0;i<5;i++)
        {
            scanf(" %c",&str[i]);
        }
        printf("\n");

        for(j=1;j<=5;j++)
        {
            for(i=0;i<5-j;i++)
            {
                printf(".");
            }
            for(i=0;i<j;i++)
            {
                printf("%c",str[i]);
            }
            printf("\n");
        }
    }
    return 0;
}
  1. chars scanf format specifier changed to " %c" to consume the '\n' left into stdin by first scanf
  2. The outer for loop must loop 5 times, so condition was changed to <= due to the started value that is 1
  3. Moved printf("\n"); inside the outer for loop.

INPUT

1
geeks

OUTPUT

....g
...ge
..gee
.geek
geeks

other test

INPUT

2
1234567890

OUTPUT

....1
...12
..123
.1234
12345

....6
...67
..678
.6789
67890
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