woockashek woockashek - 9 months ago 39
C++ Question

Detecting type of data in c++ array

Here's the c++ code printing out the buf array, filled with 0, 1, 2, ... 254

#include <iterator>
#include <iostream>
#include <numeric>

int main()
int buf[255];

auto it_b = std::begin(buf);
auto it_e = std::end(buf);

std::iota(it_b, it_e, 0);
std::copy(it_b, it_e, std::ostream_iterator<decltype(*it_b)>(std::cout, " "));

std::cout << std::endl;

return 0;

I tried to make it generic so there's only one place where the type is explicilty given

As I need to explicilty declare the type for
I wonder what is the best way to achieve this.

  1. decltype(*it_b)

  2. decltype(buf[0])

  3. something other ...

What are the pros/cons of using this or that method?

For this time assume that we are stuck with C-style arrays.

Answer Source

To be rigorously correct, you should use std::iterator_traits:

std::copy(it_b, it_e, std::ostream_iterator<
    typename std::iterator_traits<decltype(it_b)>::value_type
>(std::cout, " "));

One problem with decltype(*it_b) alone is that it will return a reference in most cases, and that would mess with the outer template that you're instantiating. You could remove the reference by hand, too:

std::copy(it_b, it_e, std::ostream_iterator<
>(std::cout, " "));