Nicholas Nicholas - 10 months ago 64
C++ Question

Error using std::bind and std::function in C++

I attempt to try my snippet of Newton's method on a multivariate function and used

. But I was stuck on an error

error: conversion from 'std::_Bind_helper&, int>::type {aka
std::_Bind, int))(double, double,
double)>}' to non-scalar type 'std::function'

What does this error message mean and how should I fix my current code?

#include <iostream>

double newton(std::function<double(double)> F, std::function<double(double)> f,
double x=0, int maxiter=1000, double epsilon=0.001)
int n = 0;
while((n < maxiter) && (fabs(F(x)) > epsilon))
x = x - F(x) / f(x);
return x;

// I'd like to fix x and z at 1 and 2 and find root for y
double ftest(double x, double y, double z)
return x * x + (y * y - 2 * y - 4) + z * z;

// Partial derivative of ftest with regards to y
double ftest1(double y)
return 2 * y - 2;

int main()
using namespace std::placeholders;
std::function<double(double)> F = std::bind(ftest, 1, _2, 2);
std::function<double(double)> f = ftest1;
std::cout << newton(F, f);
return 0;

Answer Source

The problem here:

std::function<double(double)> F = std::bind(ftest, 1, _2, 2);

is that F is a function that takes a single argument of type double, but your bind expression involves _2 - which refers to the second argument passed to the function object that bind() returns. That is, the second argument. Basically, you're constructing this function object, roughly:

struct {
    template <class T, class U>
    auto operator()(T, U arg) {
        return ftest(1, arg, 2);

That object takes two arguments. std::function<double(double)> doesn't allow for that - it requires that your callable allow for a single argument.

The simple fix is to fix the placeholder:

std::function<double(double)> F = std::bind(ftest, 1, _1, 2);

or, better, just don't use bind() at all and prefer a lambda:

std::function<double(double)> F = [](double y) { return ftest(1, y, 2); }